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The topological susceptibility χ is the order parameter of a quantum phase transition. Based on the QCD Lagrangian density with a θ-term [43, 44]:
$ \mathcal {L} = -{1\over 4} F_{\mu\nu}^a F_a^{\mu\nu}+\bar\psi\left({\rm i}\gamma^\mu D_\mu-m\right)\psi+\theta Q. $
(1) With the gluon field tensor
$ F^a_{\mu\nu} $ in both Dirac and color spaces ($\mu,\nu=0,1,2,3;\ a=0,1,2,\cdots,8$ ), we consider the covariant derivative$ D_\mu $ . The quark mass matrix, denoted as$ m=\text{diag}(m_q,m_q,m_s) $ , is defined in flavor space with light quarks$ q=u, d $ and strange quark s. We also account for vacuum angle θ and topological charge density Q , which can be defined as$ Q(x) = \frac{g^2}{32\pi^2}F^a_{\mu\nu}(x)\tilde F_a^{\mu\nu}(x), $
(2) the vacuum energy density of QCD is the path integral of the action of the system,
$ \varepsilon=-\frac{1}{V}\ln\int\mathcal{D}A_\mu\mathcal{D}\bar\psi\mathcal{D}\psi {\rm e}^{\int {\rm d}^4x\mathcal{L}} $
(3) in four dimensional space volume V, and the susceptibility χ can be formally defined as
$ \chi = {\partial^2\varepsilon\over \partial\theta^2}\Big|_{\theta=0}= \int {\rm d}^4x\langle\mathcal{T}\left[Q(x)Q(0)\right]\rangle_{\rm connected}, $
(4) where
$ \mathcal{T} $ denotes the time-ordering operator,$ \langle\cdots\rangle $ denotes ensemble average, and only connected diagrams contribute to the susceptibility.The topological charge Q corresponds to an infinite small
$ U_A(1) $ transformation for the quark field,$\psi\to {\rm e}^{{\rm i}\theta\gamma_5T_0}\psi\to \psi-{\rm i}\theta\gamma_5\psi/\sqrt 6$ , where$ T_a $ denotes the Gell-Mann matrices with the unit matrix$ T_0=\sqrt{1/6} $ , normalization$ \text{Tr}(T_aT_b)=\delta_{ab}/2 $ , equations$ \{T_a,T_b\}=d_{abc}T^c $ and$[T_a,T_b]={\rm i}f_{abc}T^c$ , and symmetric and anti-symmetric structure constants$ d_{abc} $ and$ f_{abc} $ ($ d_{ab0}=\sqrt{2/3}\delta_{ab} $ and$ f_{ab0}=0 $ ). Under this transformation, the axial current$ J^5_\mu=\bar\psi\gamma_\mu\gamma_5\psi $ is not conserved:$ \partial^\mu J^5_\mu=2N_fQ+2{\rm i}\bar\psi m\gamma_5\psi. $
(5) We now derive the hadronic version of the susceptibility (4) in the
$S U_3\times S U_3$ quark-meson model, following Ref. [25]. The model is defined as [39−41]:$ \begin{array}{*{20}{l}} \mathcal{L}_{QM} = \mathcal{L}_Q+\mathcal{L}_M \end{array} $
(6) with the meson section
$ \begin{aligned}[b] \mathcal{L}_M=& \text{Tr}\left(\partial_\mu\phi^\dagger\partial^\mu\phi\right)-\lambda^2\text{Tr}\left(\phi^\dagger\phi\right)-\lambda_1\left(\text{Tr}(\phi^\dagger\phi)\right)^2\\& -\lambda_2\text{Tr}\left(\phi^\dagger\phi\right)^2+\text{Tr}\left(H(\phi^\dagger+\phi)\right)+c\left(\text{det}(\phi^\dagger)+\text{det}(\phi)\right) \end{aligned}$
(7) and quark section
$ \mathcal{L}_Q = \bar\psi\left[{\rm i}\gamma^\mu\left(\partial_\mu-{\rm i}{\mu_B\over 3}\delta_\mu^0\right)-gT^a\left(\sigma_a+{\rm i}\gamma_5\pi_a\right)\right]\psi. $
(8) In the meson part, ϕ denotes a complex
$ 3\times 3 $ matrix composed of scalar and pseudoscalar nonets$ \sigma_a $ and$ \pi_a $ ,$\phi=T^a\phi_a=T^a(\sigma_a+{\rm i}\pi_a)$ ,$ \lambda^2 $ is the mass parameter, and the coupling constants$ \lambda_1 $ and$ \lambda_2 $ characterize the interaction among the mesons. Given that we do not have strict chiral symmetry in the real world, the explicit symmetry breaking enters the model by introducing two external sources$ h_0 $ and$ h_8 $ via$ H=\text{diag}(h_0, h_0, h_8) $ . We are concerned with$ U_A(1) $ symmetry, which is explicitly broken by the determinant term with an anomaly parameter c.In the quark part, ψ is the quark field with three flavors
$ N_f=3 $ and three colors$ N_c=3 $ ,$ \mu_B (\mu_B/3) $ denotes the baryon (quark) chemical potential, and g denotes the quark-meson coupling constant in scalar and pseudoscalar channels.To obtain the hadronic version of the topological charge Q and susceptibility χ, we consider
$ U_A(1) $ transformation for the mesons in scalar and pseudoscalar channels,$\bar\psi\psi\to\bar\psi\psi-2\theta\bar\psi {\rm i}\gamma_5\psi/\sqrt 6$ and$\bar\psi {\rm i}\gamma_5\psi\to \bar\psi {\rm i}\gamma_5\psi+ 2\theta\bar\psi\psi/\sqrt 6$ , which lead to the transformation for the meson matrix$\phi\to (1+2{\rm i}\theta/\sqrt 6)\phi$ and$\text{det}(\phi)\to (1+\sqrt 6 {\rm i}\theta)\text{det}(\phi)$ . By calculating the variation of the Lagrangian density and using the Noether's theorem, the conservation law in the quark-meson model becomes [25]:$ \begin{array}{*{20}{l}} \partial^\mu J^5_\mu = -12c\text{Im}[\text{det}(\phi)]+2{\rm i}\text{Tr}[H(\phi-\phi^\dagger)]. \end{array} $
(9) The second term is due to the explicit chiral symmetry breaking at meson level in the model. Based on the comparison of the first terms in (5) for QCD and (9) for quark-meson model, the topological charge density in the model is as follows:
$ \begin{array}{*{20}{l}} Q(x)=-2c\text{Im}[\text{det}(\phi(x))]. \end{array} $
(10) It contains all possible products of three meson fields.
We now separate the meson field into a condensate part and fluctuation part
$ \phi_a=\langle\phi_a\rangle+\phi_a' $ . The former characterizes the spontaneous breaking of the symmetries of the system, and the latter is the particle fluctuation above the mean field. Using Wick’s theorem, the topological susceptibility (4) consists of the contributions with one, two, and three meson propagators between the space-time points$ 0 $ and x. The diagram with only condensates is not connected and then neglected. To clearly understand the relation between the chiral symmetry and$ U_A(1) $ symmetry, we divide χ into a sector with chiral condensates and sector with only meson propagators:$ \begin{array}{*{20}{l}} \chi=\chi_C+\chi_M \end{array} $
(11) with
$ \begin{aligned}[b] \chi_C &= \chi_C^{(1)}+\chi_C^{(2)}+\chi_C^{(3)}+\chi_C^{(4)},\\ \chi_C^{(1)} &= {c^2\over 4} \sum\limits_{abcde}A_{abcde}\langle\phi_a\rangle\langle\phi_b\rangle I_c \langle\phi_d\rangle\langle\phi_e\rangle,\\ \chi_C^{(2)} &= {c^2\over 4} \sum\limits_{abcd}B_{abcd}\langle\phi_a\rangle\langle\phi_b\rangle I_c J_d,\\ \chi_C^{(3)} &= {c^2\over 4} \sum\limits_{abcd}C_{abcd}J_a I_b \langle\phi_c\rangle\langle\phi_d\rangle,\\ \chi_C^{(4)} &= {c^2\over 4} \sum\limits_{abcd}D_{abcd}\langle\phi_a\rangle I_{bc} \langle\phi_d\rangle \end{aligned} $
(12) and
$ \begin{aligned}[b] \chi_M &= \chi_M^{(1)}+\chi_M^{(2)},\\ \chi_M^{(1)} &= {c^2\over 4} \sum\limits_{abc}E_{abc}J_aI_bJ_c,\\ \chi_M^{(2)} &= {c^2\over 4} \sum\limits_{abc}F_{abc}I_{abc}, \end{aligned} $
(13) where
$A,~ B,~ C,~ D,~ E$ , and F denote the coefficients,$I_a=\int {\rm d}^4x G_a(x,0), I_{ab}=\int {\rm d}^4x G_a(x,0)G_b(x,0)$ and$I_{abc}= $ $\int {\rm d}^4x G_a(x,0)G_b(x,0)G_c(x,0)$ denote the integrated propagator productions with$ G_a(x,y)=\langle\phi_a(x)\phi_a(y)\rangle $ , and$J_a= G_a(0,0)= G_a(x,x)$ denotes the closed propagator. For simplicity in this expression and subsequent expressions, we replaced the fluctuation field$ \phi' $ by ϕ.$ \chi_C^{(i)}\ (i=1,2,3,4) $ and$ \chi_M^{(i)}\ (i=1,2) $ are diagrammatically shown in the left panel of Fig. 1.Figure 1. Diagrammatic expression of the topological susceptibility χ in quark-meson model (left panel) and NJL model (right panel). In the quark-meson model, dashed and solid lines denote chiral condensates and meson propagators, respectively. In the NJL model, the closed propagators at space-time points
$ 0 $ or x indicate chiral condensates, and the double lines are meson propagators from$ 0 $ to x.Before we analytically and numerically calculate the susceptibility in the next section, we first qualitatively analyze the relation between the chiral and
$ U_A(1) $ symmetries in chiral limit. In chiral breaking phase at low temperature and density, the chiral condensates and meson degrees of freedom dominate the system wherein the condensate sector$\chi_C\ \bigg(\chi_C^{(1)}\sim \langle\phi_a\rangle^4, $ $\chi_C^{(2)},~ \chi_C^{(3)}, ~ \chi_C^{(4)}\sim \langle\phi_a\rangle^2\bigg)$ and meson sector$ \chi_M $ are nonzero, and$ U_A(1) $ symmetry is broken. With increasing temperature or baryon chemical potential of the system, the light meson condensate disappears initially at$ T_c $ or$ \mu_B^c $ . However, the strange meson condensate is still nonzero due to the fact that the strange quark is much heavier than the light quarks$ m_s\gg m_q $ . In this case, the$ U_A(1) $ symmetry is still broken as induced by the nonzero$ \chi_C $ and$ \chi_M $ . When the temperature or density increases further with$ T\gg T_c $ or$ \mu_B\gg \mu_B^c $ , the strange meson condensate disappears in the very hot or dense medium, condensate sector$ \chi_C $ vanishes completely, and susceptibility is fully controlled by the meson fluctuation part$ \chi_M $ . In finite-temperature field theory, a Feynman diagram with a particle loop contributes a factor of particle number distribution n (Bose-Einstein distribution$ n_B $ or Fermi-Dirac distribution$ n_F $ ). Please refer to any textbook, such as Ref. [45], for more details. Furthermore, detailed calculations are provided in the next section. For the Feynman diagrams in$ \chi_M $ , shown in Fig. 1, a meson loop, corresponding to a gluon loop in QCD, contributes a Bose-Einstein distribution$n_B(\epsilon_a^p)= 1/({\rm e}^{\epsilon_a^p/T}-1)$ with meson energy$ \epsilon_a^p=\sqrt{m_a^2+{{p\mathit{\boldsymbol{}}}}^2} $ . It should be noted that the quark chemical potential$ (\mu_B/3) $ does not enter the quark-antiquark pair distribution. At zero temperature, there is no thermal excitation of mesons ($ n_B=0 $ ), and therefore the meson sector$ \chi_M $ disappears. This implies that, the$ U_A(1) $ symmetry can be restored strictly only by the density effect at zero temperature.The aforementioned conclusion also applies to the NJL model at quark level. In the three-flavor NJL model [42], the
$ U_A(1) $ symmetry is broken by a six-quark interaction with a coupling constant K. Under the$ U_A(1) $ transformation, the topological charge can be directly derived [12]:$ \begin{array}{*{20}{l}} Q(x) = 2K\text{Im}\ \text{det}\left[\bar\psi(x)(1-\gamma_5)\psi(x)\right] \end{array} $
(14) with all possible products of six quark fields at space-time point x. The corresponding Feynman diagrams for the condensate sector
$ \chi_C^{(i)} $ and meson sector$ \chi_M^{(i)} $ of the susceptibility χ are shown in the right panel of Fig. 1. In comparison with the left panel, the diagrams in the NJL model are very similar to that in the quark-meson model: the meson condensates$ \langle\phi_a\rangle $ (dashed lines) now become the quark-antiquark condensate$ \langle\bar q q\rangle $ and$ \langle\bar s s\rangle $ (closed quark propagators at$ 0 $ or x), and the mesons (solid lines) are constructed by quarks via random phase approximation [42] at order$ \mathcal O(1/N_c) $ (double lines). Given that the susceptibilities in the two models have the same structure, we again conclude that the$ U_A(1) $ symmetry breaking can only be restored by pure baryon density effect. The detailed calculation on the$ U_A(1) $ symmetry at finite temperature in the NJL-type model can be seen in Refs. [12−21, 23, 24, 30]. -
In this section, we analytically and numerically calculate the topological susceptibility in the quark-meson model at finite baryon density. We will address calculations in the real world that involve explicit chiral symmetry breaking. Given that the susceptibility is dependent on the condensates, as well as meson and quark masses, we will first provide a brief overview of the condensates and masses using the mean field approximation. Detailed calculations can be sourced from existing literature [41].
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After the separation of the meson field into a condensate part and fluctuation part
$ \phi=\langle\phi\rangle+\phi' $ , a meson potential$ V_M(\langle\phi\rangle) $ [40, 41] appears in the Lagrangian$ \mathcal L_M $ . At mean field level, it is the thermodynamic potential of the system$ \Omega_M=V_M $ . Considering the thermodynamics from the free constituent quarks with mass:$ \begin{array}{*{20}{l}} m=gT^a\left(\langle\sigma_a\rangle+{\rm i}\gamma_5\langle\pi_a\rangle\right), \end{array} $
(15) the thermodynamic potential of the quark-meson system becomes
$ \begin{array}{*{20}{l}} \Omega=\Omega_M+\Omega_Q \end{array} $
(16) with
$ \Omega_Q = 2N_cT\sum\limits_f\int \frac{{\rm d}^3 {{p\mathit{\boldsymbol{}}}}}{(2\pi)^3}\left[\ln\left(1-n_F(\epsilon_f^p)\right)+\ln\left(1-\bar n_F(\epsilon_f^p)\right)\right], $
(17) where
$n_F=1/({\rm e}^{(\epsilon_f^p-\mu_B/3)/T}+1)$ and$\bar n_F=1/({\rm e}^{(\epsilon_f^p+\mu_B/3)/T}+1)$ denote the Fermi-Dirac distributions for constituent quarks and anti-quarks, and$ \epsilon_f^p=\sqrt{m_f^2+{{p\mathit{\boldsymbol{}}}}^2} $ denotes the quark energy with flavor f.The physical condensates as functions of temperature and baryon chemical potential
$ \langle\phi_a\rangle(T,\mu_B) $ are determined by minimizing the thermodynamic potential:$ {\partial\Omega\over \partial \langle\phi_a\rangle} =0,\quad\quad {\partial^2\Omega\over \partial \langle\phi_a\rangle^2}>0. $
(18) In the mean field approximation, the meson masses can be directly derived from the quadratic term in the Lagrangian
$ \tilde m_a^2=\partial^2\mathcal L/\partial\phi_a^2|_{\phi=0} $ , which is equivalent to the second coefficient of the Taylor expansion of$ \Omega_M(\langle\phi\rangle) $ around the physical condensate determined by the gap equation (18),$ \tilde m_a^2=\partial^2\Omega_M/\partial\langle\phi_a\rangle^2 $ . To contain the contribution from quark thermodynamics to meson masses, one phenomenological approach to go beyond the mean field is to extend the second order derivative from$ \Omega_M $ to the total potential Ω [41],$ m_a^2={\partial^2\Omega\over \partial\langle\phi_a\rangle^2}=\tilde m_a^2+{\partial^2\Omega_Q\over\partial\langle\phi_a\rangle^2}. $
(19) Given that we focus on the chiral symmetry and
$ U_A(1) $ symmetry in this study, we introduce only the chiral condensates$ \langle\sigma_0\rangle $ and$ \langle\sigma_8\rangle $ in the following. Considering the mixing between$ \phi_0 $ and$ \phi_8 $ , normally a rotation in this subspace is considered. The two condensates are changed to the chiral condensate$ \langle\sigma\rangle_c= 1/ \sqrt 3(\sqrt 2\langle\sigma_0\rangle+ \langle\sigma_8\rangle) $ and strange condensate$\langle\sigma\rangle_s=1/ \sqrt 3(\langle\sigma_0\rangle- \sqrt 2\langle\sigma_8\rangle)$ , which leads to the constituent mass$ m_q=g\langle\sigma\rangle_c/2 $ for light quarks and$ m_s=g\langle\sigma\rangle_s/\sqrt 2 $ for strange quarks. In the pseudoscalar channel,$ \pi_0 $ and$ \pi_8 $ are rotated to the experimentally measured mesons η and$ \eta' $ via$\pi_0=\cos\theta_p\eta'- \sin\theta_p\eta$ and$ \pi_8=\sin\theta_p\eta'+\cos\theta_p\eta $ with the rotation angle$ \theta_p $ .With the choice of condensates and under the rotation, the four independent pseudoscalar meson masses in mean field approximation,
$ \tilde m_\pi^2 $ for$ a=1,2,3 $ ,$ \tilde m_K^2 $ for$ a=4,5,6,7 $ ,$ \tilde m_{\eta'}^2 $ and$ \tilde m_\eta^2 $ , can be explicitly expressed in terms of the chiral and strange condensates,$ \begin{aligned}[b] \tilde m_\pi^2 &= \lambda^2+\lambda_1\left(\langle\sigma\rangle_c^2+\langle\sigma\rangle_s^2\right)+\frac{\lambda_2}{2} \langle\sigma\rangle_c^2-\frac{c}{\sqrt 2} \langle\sigma\rangle_s,\\ \tilde m_K^2 &= \lambda^2+\lambda_1\left(\langle\sigma\rangle_c^2+\langle\sigma\rangle_s^2\right)\\&\quad +\frac{\lambda_2}{2}\left(\langle\sigma\rangle_c^2-\sqrt 2\langle\sigma\rangle_c \langle\sigma\rangle_s +2\langle\sigma\rangle_s^2\right) -\frac{c}{2}\langle\sigma\rangle_c,\\ \tilde m_{\eta'}^2 &= m_{00}^2\cos^2\theta_p+m_{88}^2\sin^2\theta_p+2m_{08}^2\sin\theta_p\cos\theta_p,\\ \tilde m_\eta^2 &= m_{00}^2\sin^2\theta_p+m_{88}^2\cos^2\theta_p-2m_{08}^2\sin\theta_p\cos\theta_p \end{aligned} $
(20) with
$ \begin{aligned}[b] m_{00}^2 &= \lambda^2+\lambda_1\left(\langle\sigma\rangle_c^2+\langle\sigma\rangle_s^2\right)+{\lambda_2\over 3}\left(\langle\sigma\rangle_c^2+\langle\sigma\rangle_s^2\right)\\ &\quad +\frac{\sqrt 2c}{3}\left(\sqrt 2\langle\sigma\rangle_c+\langle\sigma\rangle_s\right),\\ m_{88}^2 &= \lambda^2+\lambda_1\left(\langle\sigma\rangle_c^2+\langle\sigma\rangle_s^2\right)+{\lambda_2\over 6}\left(\langle\sigma\rangle_c^2+4\langle\sigma\rangle_s^2\right)\\ &\quad -\frac{\sqrt 2c}{6}\left(2\sqrt 2\langle\sigma\rangle_c-\langle\sigma\rangle_s\right),\\ m_{08}^2 &= \frac{\sqrt 2\lambda_2}{6}\left(\langle\sigma\rangle_c^2-2\langle\sigma\rangle_s^2\right)-\frac{\sqrt 2c}{6}\left(\langle\sigma\rangle_c-\sqrt 2\langle\sigma\rangle_s\right) \end{aligned} $
(21) and the mixing angle
$ \tan 2\theta_p = 2m_{08}^2/(m_{00}^2-m_{88}^2) $ . Similarly, we can obtain the scalar meson masses [41]$ m_{a_0}^2, m_\kappa^2, m_\sigma^2 $ , and$ m_{f_0}^2 $ .The model parameters
$ \lambda^2, \lambda_1, \lambda_2, h_c, h_s, c $ , and g, and condensates$ \langle\sigma\rangle_c $ and$ \langle\sigma\rangle_s $ in vacuum should to be fixed by fitting the meson properties in vacuum. By choosing the pseudoscalar meson masses$ m_\pi=135 $ MeV,$ m_K=496 $ MeV,$ m_\eta=539 $ MeV, and$ m_{\eta'}=963 $ MeV and the decay constants$ f_\pi=92.4 $ MeV and$ f_K=113 $ MeV [46], we can determine six of them, namely the meson coupling constant$ \lambda_2 $ ,$ \begin{aligned}[b] \lambda_2 &= \frac{3\left(2f_K-f_\pi\right)m_K^2-\left(2f_K^2+f_\pi\right)m_\pi^2-2\left(m_\eta^2+m_{\eta^\prime}^2\right)\left(f_K-f_\pi\right)} {\left[3f_\pi^2+8f_K\left(f_K-f_\pi\right)\right]\left(f_K-f_\pi\right)}\\& = 46.4881, \\[-16pt] \end{aligned}$
(22) parameter c controlling
$ U_A\left(1\right) $ symmetry breaking,$ c=\frac{m_K^2-m_\pi^2}{f_K-f_\pi}-\lambda_2\left(2f_K-f_\pi\right)=4807.24\; \text{MeV}, $
(23) parameters
$ h_c $ and$ h_s $ governing chiral symmetry breaking,$ \begin{aligned}[b] h_c &= f_\pi m_\pi^2 = (120.729\ \text{MeV})^3,\\ h_s &= \sqrt{2}f_Km_K^2-\frac{f_\pi m_\pi^2}{\sqrt{2}} = (336.406\ \text{MeV})^3, \end{aligned}$
(24) and chiral condensates
$ \langle\sigma\rangle_c $ and$ \langle\sigma\rangle_s $ :$ \begin{aligned}[b] \langle\sigma\rangle_c &= f_\pi = 92.4\ \text{MeV},\\ \langle\sigma\rangle_s &= \frac{1}{\sqrt{2}}\left(2f_K-f_\pi\right) = 94.48\ \text{MeV}. \end{aligned} $
(25) To determine the other meson coupling
$ \lambda_1 $ and mass parameter$ \lambda^2 $ , scalar mesons are required. Considering$ m_\sigma=550 $ MeV, we obtain$ \lambda^2=(393.945\ \text{MeV})^2 $ and$ \lambda_1= -0.771779 $ . The quark-meson coupling g and strange quark mass$ m_s $ are further associated with the non-strange quark mass$ m_q $ . By choosing$ m_q=300 $ MeV, we obtain$ g = 6.4 $ and$ m_s=433 $ MeV.As the
$ 1/N_c $ realization of the t’Hooft instanton mechanism, the Witten–Veneziano (WV) formula [47, 48] is as follows:$ \chi_{\text{pure}} = {m_\eta^2+m_{\eta'}^2-2m_K^2\over 2N_f}f_\pi^2 + \mathcal{O}\left(\frac{1}{N_c}\right). $
(26) This can be applied to estimate the
$ U_A(1) $ symmetry breaking in vacuum through the pseudoscalar meson masses and pion decay constant (It should be noted that the susceptibility in the WV formula is for the pure Yang-Mills theory). The formula is confirmed by effective methods [12, 13] and lattice QCD calculations [49−51]. In our calculation, the above used parameters leads to$ \chi=(191.033 \;\text{MeV})^4 $ , which is in good agreement with the lattice result$\chi=(191\pm 5 \;\text{MeV})^4$ in continuum limit [49]. However, it is claimed that the WV formula cannot be extended to finite temperature, especially near the QCD critical point [52, 53].With the known parameters, we now numerically calculate the density and temperature dependence of the two scalar condensates, and the result is shown in Fig. 2. Governed by the Fermi surface at zero temperature, the chiral condensate retains its vacuum value at low densities and then abruptly drops to a significantly lower value upon reaching the critical chemical potential
$ \mu_B^c=0.91 $ GeV, and then decreases smoothly. For the strange condensate, there is also a jump at$ \mu_B^c $ , but it is still large in the chiral restoration phase. As the temperature increases, the abrupt changes in the two condensates gradually diminish, transitioning the chiral phase from a distinct jump to a crossover. In sufficiently hot conditions, this crossover occurs at zero baryon density.Figure 2. (color online) Chiral and strange condensates
$ \langle\sigma\rangle_c $ (solid lines) and$ \langle\sigma\rangle_s $ (dashed lines) as functions of baryon chemical potential$ \mu_B $ at temperature T=0 (upper panel), 0.1 (middle panel), and 0.2 (lower panel) GeV.The density and temperature dependence of the pseudoscalar meson masses is shown in Fig. 3. At zero temperature, all the masses consistently retain their vacuum values below the critical chemical potential. However, they abruptly increase or decrease at the chiral phase transition point
$ \mu_B^c $ and change continuously afterwards. The strange meson K is heavier than the pseudo-Goldstone particle π in the chiral breaking phase at low density. However, the two masses approach each other in the chiral restoration phase when the chemical potential is larger than the strange quark mass. The large mass splitting between η and$ \eta' $ at low density is induced by the$ U_A(1) $ breaking. At the critical point,$ m_\eta $ experiences an upward shift while$ m_{\eta'} $ decreases, and the disparity between them decreases as density increases. When the temperature effect is included, all the jumps will gradually be replaced by continuous changes. -
The susceptibility χ varies based on density and temperature, influenced by the condensates, meson masses, and the loop induced Bose-Einstein distribution
$ n_B $ . We first calculate the four independent meson constituents shown in Fig. 1, namely the closed meson propagator$ J_a $ , meson propagator with zero momentum$ I_a $ , meson loop constructed by two mesons$ I_{ab} $ , and double meson loops by three mesons$ I_{abc} $ ,$ \begin{aligned}[b] J_a &= \int {{\rm d}^3{{p\mathit{\boldsymbol{}}}}\over (2\pi)^3}{n_B(\epsilon_a^p)\over \epsilon_a^p},\\ I_a &= \frac{1}{m_a^2}, \\ I_{ab} &= \int{{\rm d}^3{{p\mathit{\boldsymbol{}}}}\over (2\pi)^3}\frac{1}{m_b^2-m_a^2}\left[\frac{n_B(\epsilon_a^p)}{\epsilon_a^p}-\frac{n_B(\epsilon_b^p)}{\epsilon_b^p}\right],\\ I_{abc} &= I_{abc}^{(1)}+I_{abc}^{(2)}. \end{aligned}$
(27) The term
$ I_{abc} $ contains two four-momentum integrations (two Matsubara frequency summations and two three-momentum integrations), and each frequency summation contributes a constant and meson distribution$ n_B $ . After considering a renormalization to remove the divergence appeared in the$ n_B $ -independent integration [54],$ I_{abc} $ is separated into a part$ I_{abc}^{(1)} $ with one meson distribution and a part$ I_{abc}^{(2)} $ with two distributions,$ \begin{aligned}[b] I_{abc}^{(1)} =& {1\over (4\pi)^2}\sum\limits_{\{abc\}}\Bigg\{-\gamma_E+\ln(4\pi)-\ln\left({m_c^2\over \mu^2}\right)-\int_0^1 {\rm d}\alpha\Bigg[\alpha{m_a^2\over m_c^2}\\& +(1-\alpha){m_b^2\over m_c^2}-\alpha(1-\alpha)\Bigg]\Bigg\}\int{{\rm d}^3{{p\mathit{\boldsymbol{}}}}\over (2\pi)^3}{n_B(\epsilon_c^p)\over \epsilon_c^p}, \end{aligned} $
$ \begin{aligned}[b] I_{abc}^{(2)} =& 2\pi^2\sum\limits_{\{abc\}}\int{{\rm d}^3{{p\mathit{\boldsymbol{}}}}\over (2\pi)^3}{{\rm d}^3{{q\mathit{\boldsymbol{}}}}\over (2\pi)^3}{{{p\mathit{\boldsymbol{}}}}\cdot{{q\mathit{\boldsymbol{}}}}n_B(\epsilon_a^p)n_B(\epsilon_b^q)\over \epsilon_a^p\epsilon_b^q}\\& \times\ln\left|{\left(\epsilon_a^p+\epsilon_b^q\right)^2-\left(\epsilon_c^{p+q}\right)^2\over \left(\epsilon_a^p+\epsilon_b^q\right)^2-\left(\epsilon_c^{p-q}\right)^2}{\left(\epsilon_a^p-\epsilon_b^q\right)^2-\left(\epsilon_c^{p+q}\right)^2\over \left(\epsilon_a^p-\epsilon_b^q\right)^2-\left(\epsilon_c^{p-q}\right)^2}\right|, \end{aligned} $
(28) where
$ \gamma_E $ denotes the Euler constant, the renormalization scale μ is considered to be 0.3 GeV in the calculation, and the sum is defined as$ \sum _{\{abc\}}X_{abc}=X_{abc}+X_{bca}+X_{cab} $ .With the mixing angels
$ \theta_s $ and$ \theta_p $ in the scalar and pseudiscalar channels, we define the diagonalization coefficients as follows:$ \begin{aligned}[b] c_1 & = \sqrt{1/3}\left(\cos\theta_s-\sqrt 2\sin\theta_s\right),\; c_2 = \sqrt{1/3}\left(\sin\theta_s+\sqrt 2\cos\theta_s\right),\\ c_3 & = \sqrt{1/3}\left(\cos\theta_p-\sqrt 2\sin\theta_p\right),\; c_4 = \sqrt{1/3}\left(\sin\theta_p+\sqrt 2\cos\theta_p\right),\end{aligned} $
(29) the vertexes of the Feynman diagrams in Fig. 1 can then be expressed as
$ \begin{aligned}[b] c_{\eta\sigma\langle\sigma\rangle_c} &=\sqrt 2/3 \left(2\sqrt 2\sin(\theta_p+\theta_s)+\cos(\theta_p+\theta_s)\right),\\ c_{\eta f_0\langle\sigma\rangle_c} &= \sqrt 2/3 \left(2\sqrt{2}\cos(\theta_p+\theta_s)-\sin(\theta_p+\theta_s)\right),\end{aligned} $
$ \begin{aligned}[b] c_{\eta'\sigma\langle\sigma\rangle_c} &= -c_{\eta f_0\langle\sigma\rangle_c},\\ c_{\eta'f_0\langle\sigma\rangle_c} &= c_{\eta\sigma\langle\sigma\rangle_c},\\ c_{\eta\sigma\langle\sigma\rangle_s} &= \sqrt 2/6\Big(3\sin(\theta_p-\theta_s)-2\sqrt 2\cos(\theta_p+\theta_s)\\ &\quad +\sin(\theta_p+\theta_s)\Big),\\ c_{\eta f_0\langle\sigma\rangle_s} &=-\sqrt 2/6\Big(3\cos(\theta_p-\theta_s)-2\sqrt 2\sin(\theta_p+\theta_s)\\ &\quad -\cos(\theta_p+\theta_s)\Big),\\ c_{\eta'\sigma\langle\sigma\rangle_s} &= -\left(c_{\eta f_0\langle\sigma\rangle_s}+\sqrt 2\cos(\theta_p-\theta_s)\right),\\ c_{\eta' f_0\langle\sigma\rangle_s} &= c_{\eta\sigma\langle\sigma\rangle_s}-\sqrt 2\sin(\theta_p-\theta_s) \end{aligned} $
(30) for the vertexes with one condensate leg, and
$ \begin{aligned}[b] c_{\eta\eta\eta} &= -1/\sqrt 2c_3^2c_4,\\ c_{\eta\eta\eta'} &= 1/\sqrt 2\left(c_3^3-2c_3c_4^2\right),\\ c_{\eta\eta'\eta'} &= 1/\sqrt 2\left(2c_3^2c_4-c_4^3\right),\\ c_{\eta'\eta'\eta'} &= 1/\sqrt 2c_3c_4^2,\\ c_{\eta\sigma\sigma} &= 1/\sqrt 3\Big(\cos\theta_p(\sin^2\theta_s+1/\sqrt 2\sin 2\theta_s)\\ &\quad +\sqrt 2\sin\theta_p(\cos^2\theta_s-1/2\sin^2\theta_s)\Big),\\ c_{\eta\sigma f_0} &= 1/\sqrt 3\Big(\cos\theta_p(\sin 2\theta_s+\sqrt 2\cos2\theta_s)\\ &\quad -3/\sqrt 2\sin\theta_p\sin2\theta_s\Big),\\ c_{\eta f_0f_0} &= 1/\sqrt 3\Big(\cos\theta_p(\cos^2\theta_s-1/\sqrt 2\sin 2\theta_s)\\ &\quad +\sqrt 2\sin\theta_p(\sin^2\theta_s-1/2\cos^2\theta_s)\Big),\\ c_{\eta'\sigma\sigma} &= 1/\sqrt 3\Big(\sin\theta_p(\sin^2\theta_s+1/\sqrt 2\sin 2\theta_s)\\ &\quad -\sqrt 2\cos\theta_p(\cos^2\theta_s-1/2\sin^2\theta_s)\Big),\\ c_{\eta'\sigma f_0} &= 1/\sqrt 3\Big(\sin\theta_p(\sin2\theta_s+\sqrt 2\cos2\theta_s)\\ &\quad +3/\sqrt 2\cos\theta_p\sin2\theta_s\Big),\\ c_{\eta'f_0f_0} &= 1/\sqrt 3\Big(\sin\theta_p(\cos^2\theta_s-1/\sqrt 2\sin 2\theta_2)\\ &\quad -\sqrt 2\cos\theta_p(\sin^2\theta_s-1/2\cos^2\theta_s)\Big) \end{aligned} $
(31) for the vertexes without condensate legs. Finally, we define two new condensates
$ \begin{aligned}[b] \langle\sigma^2_\eta\rangle &= 1/\sqrt 6\langle\sigma\rangle_c\Big((\sqrt 2\cos\theta_p+\sin\theta_p)\langle\sigma\rangle_c\\ &\quad +2(\sqrt 2\sin\theta_p-\cos\theta_p)\langle\sigma\rangle_s\Big),\\ \langle\sigma^2_{\eta'}\rangle &= 1/\sqrt{6}\langle\sigma\rangle_c\Big((\sqrt 2\sin\theta_p-\cos\theta_p)\langle\sigma\rangle_c\\ &\quad -2(\sqrt 2\cos\theta_p+\sin\theta_p)\langle\sigma\rangle_s\Big), \end{aligned} $
(32) and explicitly write the different susceptibility terms.
$ \begin{aligned}[b] \chi_C^{(1)} &= {c^2\over 4}\Big[\langle\sigma^2_\eta\rangle^2I_\eta+\langle\sigma^2_{\eta'}\rangle^2I_{\eta'}\Big],\\ \chi_C^{(2)} &= {c^2\over 4}\Big[\langle\sigma^2_\eta\rangle\Big(6c_{\eta\eta\eta}J_\eta+2c_{\eta\eta'\eta'}J_{\eta'}+2c_{\eta\sigma\sigma}J_\sigma+2c_{\eta f_0 f_0}J_{f_0} +4c_3(J_\kappa-J_K)+3\sqrt 2c_4(J_\pi-J_{a_0})\Big)I_\eta\\ &\quad +\langle\sigma^2_{\eta'}\rangle\Big(6c_{\eta'\eta'\eta'}J_{\eta'}+2c_{\eta\eta\eta'}J_\eta+2c_{\eta'\sigma\sigma}J_\sigma+2c_{\eta' f_0 f_0}J_{f_0}+ 3\sqrt 2 c_3(J_{a_0}-J_\pi)+4c_4(J_\kappa-J_K) \Big)I_{\eta'}\Big],\\ \chi_C^{(3)} &= \chi_C^{(2)},\\ \chi_C^{(4)} &= {c^2\over 4}\Big[(c_{\eta\sigma\langle\sigma\rangle_c}\langle\sigma\rangle_c+c_{\eta\sigma\langle\sigma\rangle_s}\langle\sigma\rangle_s)^2 I_{\eta\sigma}+(c_{\eta f_0\langle\sigma\rangle_c}\langle\sigma\rangle_c + c_{\eta f_0\langle\sigma\rangle_s}\langle\sigma\rangle_s)^2I_{\eta f_0}+(c_{\eta'\sigma\langle\sigma\rangle_c}\langle\sigma\rangle_c+c_{\eta'\sigma\langle\sigma\rangle_s}\langle\sigma\rangle_s)^2I_{\eta'\sigma}\\ &\quad +(c_{\eta' f_0\langle\sigma\rangle_c}\langle\sigma\rangle_c+c_{\eta' f_0\langle\sigma\rangle_s}\langle\sigma\rangle_s)^2 I_{\eta'f_0} +4\langle\sigma\rangle_c^2I_{K\kappa}+6\langle\sigma\rangle_s^2 I_{\pi a_0}\Big] \end{aligned}$
(33) for the condensate controlled part
$ \chi_C $ , and$ \begin{aligned}[b] \chi_M^{(1)} &= {c^2\over 4}\Big\{I_\eta\Big[3c_{\eta\eta\eta}\Big(3c_{\eta\eta\eta} J_\eta+2c_{\eta\eta'\eta'} J_{\eta'}+3 \sqrt 2 c_4 (J_\pi-J_{a_0})+4 c_3(J_\kappa-J_K)+2(c_{\eta\sigma\sigma}J_\sigma+c_{\eta f_0 f_0}J_{f_0})\Big)J_\eta\\ &\quad +c_{\eta\eta'\eta'}\Big(c_{\eta\eta'\eta'}J_{\eta'}+2 c_{\eta\sigma\sigma}J_\sigma+2c_{\eta f_0 f_0}J_{f_0}+3\sqrt 2c_4(J_\pi-J_{a_0})+4c_3(J_\kappa-J_K)\Big)J_{\eta'}\\ &\quad +c_{\eta\sigma\sigma}\Big(c_{\eta\sigma\sigma}J_\sigma+2c_{\eta f_0 f_0}J_{f_0}+3\sqrt{2}c_4(J_\pi-J_{a_0})+4c_3(J_\kappa-J_K)\Big)J_\sigma+c_{\eta f_0 f_0}\Big(c_{\eta f_0 f_0} J_{f_0}+3\sqrt{2}c_4(J_\pi-J_{a_0})+4c_3(J_\kappa-J_K)\Big)J_{f_0}\\ &\quad +3/2c_4^2\Big(3J_{a_0}J_{a_0}+3J_\pi J_\pi+2J_\kappa J_\kappa-6J_\pi J_{a_0}\Big)+c_3^2\Big(4J_K J_K+J_\kappa J_\kappa-8J_K J_\kappa\Big)+6\sqrt 2c_3c_4\Big(J_{a_0}J_K-J_{a_0}J_\kappa-J_\pi J_K+J_\pi J_\kappa\Big)\Big]\\ &\quad +I_{\eta'}\Big[3c_{\eta'\eta'\eta'}\Big(3c_{\eta'\eta'\eta'}J_{\eta'}+2 c_{\eta'\eta\eta} J_\eta +3\sqrt 2 c_3(J_{a_0}-J_\pi)+4 c_4 (J_\kappa-J_K)+2(c_{\eta'\sigma\sigma}J_\sigma+c_{\eta' f_0 f_0}J_{f_0})\Big)J_{\eta'}\\ &\quad +c_{\eta\eta\eta'}\Big(2c_{\eta'\sigma\sigma} J_\sigma+2 c_{\eta'f_0 f_0} J_{f_0}+3 \sqrt 2 c_3(J_{a_0}-J_\pi)+4c_4(J_\kappa-J_K) +c_{\eta\eta\eta'} J_\eta\Big)J_\eta\\ &\quad +c_{\eta'\sigma\sigma}\Big(c_{\eta'\sigma\sigma}J_\sigma+2c_{\eta' f_0 f_0}J_{f_0}+3\sqrt 2c_3(J_{a_0}-J_\pi)+4c_4(J_\kappa-J_K)\Big)J_\sigma+c_{\eta' f_0 f_0}\Big(c_{\eta' f_0 f_0}J_{f_0}+3\sqrt 2 c_3(J_{a_0}-J_\pi)+4c_4(J_\kappa-J_K)\Big)J_{f_0}\\ &\quad +c_4^2\Big(4J_K J_K+3J_\kappa J_\kappa-8J_K J_\kappa\Big)+9/2c_3^2\Big(J_{a_0}J_{a_0}+J_\pi J_\pi-2J_\pi J_{a_0}\Big)+6\sqrt 2c_3c_4\Big(J_\pi J_K-J_\pi J_\kappa-J_{a_0}J_K-J_{a_0}J_\kappa\Big)\Big]\Big\},\\ \chi_M^{(2)} &=\, {c^2\over 4}\Big[6I_{\pi K K}+6I_{\pi \kappa \kappa}+12I_{K a_0 \kappa}+6c^2_{\eta\eta\eta}I_{\eta \eta \eta}+2c^2_{\eta\eta\eta'}I_{\eta \eta \eta'}+6c^2_{\eta'\eta'\eta'}I_{\eta' \eta' \eta'}+2c^2_{\eta\eta'\eta'}I_{\eta\eta'\eta'}+2c^2_{\eta'\sigma\sigma}I_{\eta' \sigma\sigma}+2c^2_{\eta' f_0 f_0}I_{\eta'f_0f_0}\\ &\quad +c^2_{\eta'\sigma f_0}I_{\eta'\sigma f_0}+c^2_{\eta\sigma f_0}I_{\eta\sigma f_0}+2c^2_{\eta\sigma\sigma}I_{\eta\sigma\sigma}+2c^2_{\eta f_0 f_0}I_{\eta f_0 f_0}+6c_1^2I_{\sigma\pi a_0}+6c_2^2I_{f_0\pi a_0}+4c_1^2I_{f_0 K \kappa}+4c_2^2I_{\sigma K\kappa}+3c_3^2I_{\eta' a_0 a_0}\\ &\quad +3c_3^2I_{\eta'\pi\pi}+2c_4^2I_{\eta' K K}+3c_4^2I_{\eta'\kappa\kappa}+3c_4^2I_{\eta a_0 a_0}+3c_4^2I_{\eta\pi\pi}+2c_3^2I_{\eta K K}+3c_3^2I_{\eta\kappa\kappa}\Big]\\[-12pt] \end{aligned}$
(34) for the meson fluctuation controlled part
$ \chi_M $ .The topological susceptibility χ and its two components
$ \chi_C $ and$ \chi_M $ in dense and hot quark-meson matter are shown in Fig. 4. To clearly observe the$ U_A(1) $ symmetry in the chiral restoration phase, we firstly analyze the susceptibility in chiral limit and at zero temperature. In this case, the disappeared chiral condensate$ \langle\sigma\rangle_c=0 $ leads to$ \langle\sigma_\eta^2\rangle = \langle\sigma_{\eta'}^2\rangle =0 $ and in turnFigure 4. (color online) Absolute values of topological susceptibility χ (solid lines) and its condensate component
$ \chi_C $ (dashed lines) and meson component$ \chi_M $ (dotted lines) as functions of baryon chemical potential$ \mu_B $ at temperature$ T=0,\ 0.1,\ 0.2 ,$ and$ 0.3 $ GeV.$ \begin{array}{*{20}{l}} \chi_C^{(1)}=\chi_C^{(2)}=\chi_C^{(3)}=0, \end{array} $
(35) and the disappeared thermal excitation of mesons
$ n_B=0 $ results in$ J_a=I_{ab}=I_{abc}=0 $ and in turn$ \begin{array}{*{20}{l}} \chi_C^{(2)}=\chi_C^{(3)}=\chi_C^{(4)}=\chi_M^{(1)}=\chi_M^{(2)}=0. \end{array} $
(36) This indicates that the strange condensate
$ \langle\sigma\rangle_s $ does not affect$ U_A(1) $ symmetry, and the two broken symmetries, chiral symmetry and$ U_A(1) $ symmetry, are simultaneously restored at the critical chemical potential$ \mu_B^c $ . In the real world, with explicit chiral symmetry breaking at zero temperature, the nonzero chiral and strange condensates$ \langle\sigma\rangle_c $ and$ \langle\sigma\rangle_s $ lead to$ \chi=\chi_C^{(1)}\ne 0 $ in the chiral restoration phase. However, from our numerical calculation, the value is very small, and$ U_A(1) $ symmetry is almost restored, as shown in the panel with$ T=0 $ in Fig. 4.Considering the significant mass splittings among the four independent mesons depicted in Fig. 3 during the chiral restoration phase, the susceptibility calculation (26) via meson masses at the mean field level appears more problematic at finite density. It has been suggested that this approach should not be extended to finite temperature [52, 53].
As the temperature increases and the condensate part
$ \chi_C $ gradually melts, the meson fluctuation part$ \chi_M $ is enhanced by the thermal motion. As a result of the competition, the total susceptibility decreases to the low temperature region, where the condensates are strong and thermal fluctuation is weak. Subsequently, it increases to the high temperature region, where the condensates become weak and thermal fluctuation becomes strong. In contrast to this non-monotonic temperature behavior, increasing density at any fixed temperature reduces the condensates and thermal fluctuation, the topological susceptibility is suddenly (at low temperature) or smoothly (at high temperature) suppressed by the density effect, and the$ U_A(1) $ symmetry is restored at high baryon density. In the temperature and density evolution of the susceptibility, the role of the strange condensate is always weak, and the$ U_A(1) $ restoration occurs at almost the same critical point as the chiral restoration. These features are clearly shown in Fig. 4.
${\boldsymbol{ U_A(1) }}$ symmetry restoration at high baryon density
- Received Date: 2023-03-23
- Available Online: 2023-10-15
Abstract: We study the relation between chiral and