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The dynamics of the strong interaction are described by quantum chromodynamics (QCD), and hadron spectroscopy is a method of studying QCD; meanwhile, hadron spectroscopy is the basic theory of the strong interaction. Understanding the spectrum of hadron resonances [1] and establishing a connection with the QCD is one of the important goals of hadron physics. The conventional quark models in the low-lying hadron spectrum successfully explain that a baryon is a complex of three quarks, and a meson is a combination of a quark and an antiquark [2, 3]. However, even if the model provides a large amount of data about the meson and baryon resonances [2–4], we cannot rule out other more exotic components, especially considering that the QCD Lagrangian includes not only quarks but also gluons. This leads to other configurations of color singlets, such as glueballs made purely of gluons, mixed states made of quark and gluon excitations, and multiquarks. There is also the possibility of more quark states in a hadron, such as
qqˉqˉq andqqˉqqq , which are mentioned in Ref. [5]. To quantitatively understand the QCD of quarks and gluons, over the years, numerous related experiments have been conducted in search of evidence for these exotic components in the mesonic and baryonic spectrum [6–10].The triangle singularity (TS) was discussed in Ref. [11], and Landau has systematized it in Ref. [12]. The TS was fashionable in the 1960s [13–16]. In addition to ordinary hadronic, molecular, or multiquarks states, TSs can produce peaks, but these peaks are produced by kinematic effects. The Coleman-Norton theorem [17] states that the Feynman amplitude has a singularity on the physical boundary as time moves forward if the decay process can be interpreted as taking place during the conservation of energy and momentum in space-time, and all internal particles really exist on the shell. In the process of particle 1 decaying into particles 2 and 3, particle 1 first decays into particles A and B, then A decays into particles 2 and C, and finally particles B and C fuse into an external particle 3. Particles A, B, and C are intermediate particles, and if the momenta of these intermediate particles can take on-shell values, a singularity will occur. A simpler and more practical way to understand this process was proposed in Ref. [18]; this method does not compute the entire amplitude of the Feynman diagram including the triangle loop. The condition for producing a TS is
qon+=qa− , as given by Eq. (18) in Ref. [18], whereqon represents the on-shell momentum of particle A or B in the rest system of particle 1, andqa− defines one of the two solutions to the momentum of particle B when B and C produce particle 3 on the shell. Since the process of the triangle mechanism involves the fusion of hadrons, the presence of hadronic molecular states plays an important role in having measurable strength. Therefore, the study of singularity is also a useful tool to study the molecular states of hadrons.The isospin violation in production of the
f0(980) ora0(980) resonance generation and its mixing have long been controversial. We have to give up the idea of trying to establish a "f0−a0 mixing parameter" from different reactions, because it was shown that the isospin violation depends significantly on the reaction [19–22]. The spark was raised by the puzzle of the anomalously large isospin violation in theη(1450)→π0f0(980) decay [23], which was due to a TS and was explained in Refs. [21, 22]. From the point of view of thef0(980) anda0(980) themselves, the above reaction is very enlightening. These resonances are produced by the rescattering ofKˉK , i.e., the mechanism for the formation of these resonances in the chiral unitary approach [24–27]. In addition, there are numerous processes with the same mechanism, such as the processτ−→ντπ−f0(a0) [28], the processB0s→J/ψπ0f0(a0) [29], the processD+s→π+π0f0(a0) [30], and the processB−→D∗0π−f0(a0) [31], and the same TS was shown in Refs. [32, 33] to provide a plausible explanation for the peak observed in theπf0(980) final state. It is easy to envisage many reactions of this type [34], and this inspires us to find more processes like this type and search for TS enhanced isospin-violating reactions producing thef0(980) ora0(980) resonances [35].In the present study, we investigate the reactions
B0→J/ψK0f0(980) andB0→J/ψK0a0(980) ; both decay modes are allowed. The process followed by the ϕ decay intoK0ˉK0 andK0ˉK0 fuse intof0(a0) to generate a singularity, and the TS in this process contains relevant information concerning the nature of thef0(980) anda0(980) resonances. We show that it develops a TS at an invariant massMinv(K0R)≃1520 MeV . Meanwhile, we can obtaind2Γ/[dMinv(K0f0)dMinv(π+π−)] ord2Γ/[dMinv(K0a0)dMinv(π0η)] , which show the shapes of thef0 (980) anda0 (980) resonances in theπ+π− orπ0η mass distributions, respectively. We can restrict the integral inMinv(π+π−) orMinv(π0η) to this region when calculating the mass distributiond2Γ/[dMinv(K0f0)dMinv(π+π−)] ord2Γ/[dMinv(K0a0)dMinv(π0η)] . Then, we integrate over theπ+π− orπ0η invariant masses and obtain a clear peak aroundMinv(K0R)≃1520 MeV . The further integration overMinv(K0R) provides us branching ratios forB0→J/ψK0π+π−B0→J/ψK0π0η , and we find that the mass distribution of these decay processes shows a peak associated with TS. In addition, the corresponding decay branching ratio is obtained, and we obtain the branching fractionsBr(B0→J/ψK0f0(a0))=1.007×10−5 ,Br(B0→J/ψK0f0(980)→J/ψK0π+π−)=1.38×10−6 , andBr(B0→J/ψK0a0(980)→J/ψK0π0η)=2.56×10−7 . In any case, the main aim of the present work is to point out the presence of the TS in this reaction. This work provides one more measurable example of a TS, which has been quite sparse up to now. The singularity generated by this process can also play an early warning role for future experiments. -
We plot the Feynman digrams of the decay process
B0→J/ψK0f0(a0)(980) involving a triangle loop in Figs. 1 and 2. We observe that particleB0 first decays into particlesJ/ψ,ϕ,K0 , and then, particle ϕ decays intoK0 andˉK0 ; then,K0 andˉK0 fuse intof0(a0) , and eventuallyf0(a0) decays intoπ+π−(π0η) .Figure 1. Feynman diagrams of the decay process
B0→ J/ψK0f0(980)→J/ψK0π+π− involving a triangle loop.We take Fig. 1 for example to perform the following discussion, since Figs. 1 and 2 have nearly the same amplitude. Now, we want to find the position of TS in the complex-q plane, instead of evaluating the whole amplitude of a Feynman diagram including the triangle loop. Analogously to Refs. [18, 36, 37], we can use
qon+=qa−,
(1) where
qon+ represents the on shell momentum of the ϕ in the center of mass frame ofϕK0 . Meanwhile,qa− can be obtained by analyzing the singularity structure of the triangle loop;qa− represents the on-shellK0 momentum in the loop, antiparallel to the ϕ.qon+ andqa− are given byqon+=λ12(s,M2ϕ,M2K0)2√s,qa−=γ(vEK0−p∗K0)−iϵ,
(2) where s denotes the squared invariant mass of ϕ and
K0 , andλ(x,y,z)=x2+y2+z2−2xy−2yz−2xz is the Kählen function, with definitionsv=kEf0, γ=1√1−v2=Ef0mf0,EK0=m2K+1+m2K0−m2ˉK02mf0,p∗K0=λ12(m2f0,m2K0,m2ˉK0)2mf0.
(3) It is easy to realize that
EK0 andp∗K0 are the energy and momentum ofK0 in the center of mass frame of theϕK0 system, and v and γ are the velocity of thef0 and Lorentz boost factor. In addition, we can easily obtainEf0=s+m2f0−m2ˉK02√s,k=λ12(s,m2f0,m2ˉK0)2√s.
(4) The three intermediate particles must be on the shell. We let the mass of
f0 be slightly larger than the sum of the masses ofK0 andˉK0 ; now, we can determine that the mass ofK0 is497.61 MeV , the mass off0 is slightly larger than the sum of the masses ofK0 andˉK0 , and the mass off0 is991 MeV ; additionally, we can find a TS at approximately√s=1520 MeV . If we use in Eq. (1) complex masses(M−iΓ/2) of mesons that include widths ofK0 andˉK0 , the solution of Eq. (1) is then(1520−10i) MeV . This solution implies that the TS has a "width" of20 MeV . -
Here, we only focus on the
B0→J/ψϕK0 process. The decay branching ratio has been experimentally measured to be [38]Br(B0→J/ψϕK0)=(4.9±1.0)×10−5.
(5) The differential decay width over the invariant mass distribution
J/ψϕ can be written asΓB0→J/ψϕK0Minv(J/ψϕ)=1(2π)3˜pϕpK04M2B0⋅¯∑|tB0→J/ψϕK0|2,
(6) here,
˜pϕ represents the momentum of theK0 in theϕK0 rest frame, andpK0 represents the momentum of theK0 in theB0 rest frame:˜pϕ=λ12(Minv(J/ψϕ)2,m2J/ψ,m2ϕ)2Minv(J/ψϕ),
(7) pK0=λ12(M2B0,m2K0,Minv(J/ψϕ)2)2MB0.
(8) We use the polarization summation formula
∑pol=ϵμ(p)ϵν(p)=−gμν+pμpνm2,
(9) and we have
¯∑pol|tB0→J/ψϕK0|2=C2(−gμν+pμJ/ψpνJ/ψm2J/ψ)(−gμν+pμϕpνϕm2ϕ)=C2(2+(pJ/ψ⋅pϕ)2m2J/ψm2ϕ),
(10) where
pϕ⋅pJ/ψ=12(Minv(J/ψϕ)2−m2J/ψ−m2ϕ),
(11) 1ΓB0=Br(B0→J/ψϕK0)∫dΓB0dMinv(J/ψϕ)dMinv(J/ψϕ).
(12) Then, we can determine the value of the constant
C C2ΓB0=Br(B0→J/ψϕK0)∫dMinv(J/ψϕ)1(2π)3˜pϕpK04M2B0⋅(2+(pJ/ψ⋅pϕ)2m2J/ψm2ϕ),
(13) where the integration is performed from
Minv(J/ψϕ)min =mJ/ψ+mϕ toMinv(J/ψϕ)max =MB0−mK0 . -
In the previous subsection, we calculated the transition strength of the decay process
B0→J/ψϕK0 . Now, we calculate the contribution of the vertexϕ→K0ˉK0 . We can obtain thisVPP vertex from the chiral invariant Lagrangian with local hidden symmetry given in Refs. [39–42]:LVPP=−ig⟨Vμ[P,∂μP]⟩,
(14) where
⟨⟩ denotes the trace of the flavor SU(3) matrices, and g represents the coupling in the local hidden gauge.g=MV2fπ,MV=800 MeV,fπ=93 MeV.
(15) The V and P in Eq. (14) are the vector meson matrix and pseudoscalar meson matrix in the SU(3) group, respectively, which are given by
P=(π0√2+η√3+η′√6π+K+π−−π0√2+η√3+η′√6K0K−ˉK0−η√3+√23η′),V=(ρ0√2+ω√2ρ+K∗+ρ−−ρ0√2+ω√2K∗0K∗−ˉK∗0ϕ).
(16) Now, we can write the invariant mass distribution
Minv(K0f0(a0)) in the decayB0→J/ψK0f0 asdΓB0→J/ψK0f0(a0)dMinv(K0f0(a0))=1(2π)314M2B0p′J/ψ˜p′K0¯∑∑|t|2,
(17) We take the first diagram of Fig. 1 and the
B0→J/ψK0f0 decay as an example and write down its amplitude as follows:t=C∫d3q(2π)318ωK0ωϕω′K01k0−ω′K0−ωϕ×1Minv(K0f0)+ωK0+ω′K0−k0×1Minv(K0f0)−ωK0−ω′K0−k0+iΓK02×[2Minv(K0f0)ωK0+2k0ω′K0Minv(K0f0)−ωϕ−ωK0+iΓϕ2+iΓK02−2(ωK0+ω′K0)(ωK0+ω′K0+ωϕ)Minv(K0f0)−ωϕ−ωK0+iΓϕ2+iΓK02]×ggK0ˉK0f0p′J/ψ˜p′K0(2+→q⋅→k→k2),
(18) where
ω′K0=((→P−→q−→k)2+m2K0)12,
ωϕ=((→P−→q)2+m2ϕ)12,ωK0=(→q2+m2K0)12,k0=M2inv(K0f0)+m2K0−m2f02Minv(K0f0),|→k|=λ12(M2inv(K0f0),m2K0,m2f0)2Minv(K0f0).
(19) The
f0→K0ˉK0 anda0→K0ˉK0 vertices are obtained from the chiral unitary approach of Ref. [24] withgK0ˉK0f0 =2567 MeV andgK0ˉK0a0 =3875 MeV.p′J/ψ represents the momentum of theJ/ψ in theB0 rest frame, and˜p′K0=|→k| represents the momentum of theK0 in theK0f0(980) rest frame, wherep′J/ψ=λ12(M2B0,m2J/ψ,M2inv(K0f0))2MB0,
(20) ˜p′K0=λ12(M2inv(K0f0),m2K0,m2f0)2Minv(K0f0),
(21) here,
tT represents the loop amplitude:tT=∫d3q(2π)318ωK0ωϕω′K01k0−ω′K0−ωϕ×1Minv(K0f0)+ωK0+ω′K0−k0×1Minv(K0f0)−ωK0−ω′K0−k0+iΓK02×[2Minv(K0f0)ωK0+2k0ω′K0Minv(K0f0)−ωϕ−ωK0+iΓϕ2+iΓK02−2(ωK0+ω′K0)(ωK0+ω′K0+ωϕ)Minv(K0f0)−ωϕ−ωK0+iΓϕ2+iΓK02](2+→q⋅→k→k2).
(22) We have
1ΓB0dΓB0→J/ψK0f0dMinv(K0f0)=1(2π)314MB0p′J/ψ˜p′K0C2ΓB0⋅g2g2K0ˉK0f0|→k|2|tT|2=1(2π)314MB0p′J/ψ˜p′3K0C2ΓB0⋅g2g2K0ˉK0f0|tT|2.
(23) The case for
a0 production is identical, except thatgK0ˉK0f0 is replaced withgK0ˉK0a0 .The
K0ˉK0→π+π− andK0ˉK0→π0η scattering was studied in detail in Refs. [43, 44] within the chiral unitary approach, where six channels were taken into account, includingπ+π− ,π0π0 ,K+K− ,K0ˉK0 ,ηη , andπ0η . In the present study, we use this as input, and we shall see simultaneously both thef0(980) (with I = 0) anda0(980) (with I = 1) productions. Now, we can write the double differential mass distribution for the decay processB0→J/ψK0f0(980)→J/ψK0π+π− .For the case of
f0(980) , we only have the decayf0→π+π− ; thus,d2ΓB0→J/ψK0f0(980)→J/ψK0π+π−dMinv(K0f0)dMinv(π+π−)=1(2π)514M2B0p′′J/ψ˜p′′3K0˜p′′π+∑¯∑|t′|2,
(24) where
p′′J/ψ represents the momentum of theJ/ψ in theB0 rest frame,˜p′′K0 represents the momentum of theK0 in theK0f0(980) rest frame, and˜p′′π represents the momentum of the π in theπ+π− rest frame:p′′J/ψ=λ12(M2B0,m2J/ψ,M2inv(K0f0))2MB0,˜p′′K0=λ12(M2inv(K0f0),m2K0,M2inv(π+π−))2Minv(K0f0),˜p′′π=λ12(M2inv(π+π−),m2π+,m2π−)2Minv(π+π−).
(25) We can obtain the amplitude of
B0→J/ψK0f0→J/ψK0π+π− :∑¯∑|t′|2=C2g2|tK0ˉK0,π+π−|2|tT|2,
(26) where
t=[1−VG]−1V,
(27) and the V matrix is taken from Ref. [24]. Then, we obtain the double differential branching ratio of the
B0→J/ψK0f0→J/ψK0π+π− reaction:1Γd2ΓB0→J/ψK0f0→J/ψK0π+π−dM(K0f0)dMinv(π+π−)=C2ΓB01(2π)514M2B0p′′J/ψ˜p′′3K0˜p′′π×g2|tK0ˉK0,π+π−|2|tT|2.
(28) The case for
a0 production is identical, except thattK0ˉK0,π+π− is replaced withtK0ˉK0,π0η . -
Let us begin by showing in Fig. 3 the contribution of the triangle loop to the total amplitude and the triangle loop defined in Eq. (22). In order to satisfy the TS condition of Eq. (1), all intermediate particles must be on the shell; thus, the mass sum of
K0ˉK0 must be smaller than that off0(a0) . If the mass off0(a0) is too large, Eq. (1) will not be satisfied. There is hence a very narrow window off0(a0) masses where the TS condition is exactly fulfilled, i.e., 995 to 999 MeV. The magnitude depends on thef0(a0) mass; it is independent of whether we havef0 ora0 , since the different couplings toK0ˉK0 have been factorized out of the integral oftT . From the perspective of the above considerations, we plot the real and imaginary parts oftT , as well as the absolute value withMinv(R) fixed at 986, 991, and 996 MeV. We can see that the bottom one has a clear peak, because 996 MeV is in the energy window. It can be observed that Re(tT ) has a peak around 1518 MeV, Im(tT ) has a peak around 1529 MeV, and there is a peak for|tT| around 1520 MeV. As discussed in Refs. [45, 46], the peak of the imginary part is related to the TSs, while that of the real part is related to theK0ϕ threshold.|tT|=√Re2(tT)+Im2(tT) is betweenRe(tT) andIm(tT) . Note that, at approximately 1520 MeV and above, the TS dominates the reaction.Figure 3. (color online) Triangle amplitude
tT , as a function ofMinv(K0f0/K0a0) for (a)mf0(a0) = 986 MeV, (b)mf0(a0) = 991 MeV, and (c)mf0(a0) = 996 MeV.|tT| , Re(tT ), and Im(tT ) are plotted using green, orange, and blue curves, respectively.Next, we show
1ΓJ/ψdΓB0→J/ψK0f0(a0)dMinv(K0f0/K0a0) . In Fig. 4, we plot Eq. (23) for the decay processB0→J/ψK0f0(a0) , and we see a peak around 1520 MeV. We can obtain the branching ratio of the 3-body decay process when we integrate overMinv(K0R) ,Figure 4. (color online) Differential branching ratio
1ΓB0dΓB0→J/ψK0f0dMinv(K0f0) described in Eq. (23) as a function ofMinv(K0f0/K0a0) Br(B0→J/ψK0f0(a0))=2.45×10−6.
(29) In the upper panel of Fig. 5, we plot Eq. (24) for the
B0→J/ψK0π+π− decay, and similarly, in the lower panel of Fig. 5, we plot it for theB0→J/ψK0π0η decay as a function ofMinv(R) . In both figures, we fixMinv(K0R) = 1500, 1520, and 1540 MeV and varyMinv(R) . We can see that the distribution with the highest strength is nearMinv(K0R) = 1520 MeV. We also observe a strong peak whenMinv(π+π−) is around 980 MeV in the upper panel of Fig. 5. Similar results are shown in the lower panel of Fig. 5. We see that most of the contribution to the width Γ comes fromMinv(K0R) =MR , and we have strong contributions forMinv(π+π−)∈ [500 MeV, 990 MeV] andMinv(π0η)∈ [800 MeV, 990 MeV]. Therefore, when we calculate the mass distributiondΓdMinv(K0R) , we restrict the integral to the limits already mentioned and perform the integration.Figure 5. (color online) (a)
d2ΓB0→J/ψK0f0(980)→π+π−dMinv(K0f0)dMinv(π+π−) as a function ofMinv(π+π−) . (b)d2ΓB0→J/ψK0a0(980)→J/ψK0π0ηdMinv(K0a0)dMinv(π0η) as a function ofMinv(π0η) . The blue, orange, and green curves are obtained by settingMinv(K0f0)= 1500, 1520, and 1540 MeV, respectively.1ΓB0dΓB0→J/ψK0f0(980)→J/ψK0π+π−dMinv(K0f0)=1ΓJ/ψ∫990MeV500MeVdMinv(π+π−)×d2ΓB0→J/ψK0f0(980)→J/ψK0π+π−dMinv(K0f0)dMinv(π+π−),
(30) 1ΓB0dΓB0→J/ψK0a0(980)→J/ψK0π0ηdMinv(K0a0)=1ΓJ/ψ∫990MeV800MeVdMinv(π0η)×d2ΓB0→J/ψK0a0(980)→J/ψK0π0ηdMinv(K0a0)dMinv(π0η).
(31) We show Eq. (24) for both
B0→J/ψK0π+π− andB0→J/ψK0π0η . When we integrate overMinv(R) , we obtaindΓdMinv(K0R) , which we show in Fig. 6. We see a clear peak of the distribution around 1520 MeV, forf0 anda0 production. At the same time, we observe that the peak ofMinv(K0a0) is significantly lower than the peak ofMinv(K0f0) .Figure 6. (color online) (a) Differential branching ratio
dΓB0→J/ψK0f0(980)→J/ψK0π+π−dMinv(K0f0) . (b) Branching ratiodΓB0→J/ψK0f0(980)→J/ψK0π+π−dMinv(K0a0) described in Eq. (24) as a function ofMinv(K0f0/K0a0) By integrating
dΓdMinv(K0f0) anddΓdMinv(K0a0) over theMinv(K0f0) (Minv(K0a0) ) masses in Fig. 6, we obtain the branching fractions:Br(B0→J/ψK0f0(980)→J/ψK0π+π−)=7.67×10−7,Br(B0→J/ψK0a0(980)→J/ψK0π0η)=1.42×10−7.
(32) -
We performed calculations for the reactions
B0→J/ψK0f0(980)(a0(980)) and showed that they develop a TS for an invariant mass of 1520 MeV in(K0R) . This TS shows up as a peak in the invariant mass distribution of these pairs with an apparent width of approximately 20 MeV. We applied the experimental data of the branching ratio of the decayB0→J/ψK0f0(980)(a0(980)) to determine the coupling strength of theB0→J/ψK0f0(980)×(a0(980)) vertex.We evaluated
d2ΓtotaldMinv(K0R)dMinv(R) and observed clear peaks in the distributionsMinv(π+π−) (Minv(π0η) ), clearly showing thef0(a0) shapes. With integration overMinv(R) , these distributions exhibited a clear peak forMinv(K0R) around 1520 MeV.This peak is a result of the singularity of the triangle and may be misidentified with resonance when the experiment is completed. In this sense, the present work should serve as a warning not to treat this peak as resonance when it is seen in future experiments. It is important to discover new conditions about TSs and to allow for this possibility when experimentally observed peaks can avoid associating these peaks with resonance. The value of this work lies in identifying a TS for a suitable reaction and then preparing the results and research to interpret the peak correctly when it is observed.
Triangle mechanism in the decay process B0→J/ψK0f0(980)(a0(980))
- Received Date: 2023-03-16
- Available Online: 2023-07-15
Abstract: The role of the triangle mechanism in the decay processes